Question

find the area of triangle whose area are 29cm , 36cm and 25 cm by using hermons formula​

Answer 1

1st Side = 29 cm

2nd Side = 36 cm

3rd Side = 25 cm

Semi Perimeter = $\frac{Perimeter}{2}$

= $\frac{29+36+25}{2}$

= $\frac{90}{2}$

= 45

Heron's Formula for finding area :

= $\sqrt{s[s-a][s-b][s-c]}$

= $\sqrt{45[45-29][45-36][45-25]}$

= $\sqrt{45 * 16 * 9 * 20}$

= $\sqrt{129600}$

= 360 cm²

∴ 360 cm² is the are of that Triangle.

Answer 2

Answer:

1st Side = 29 cm

2nd Side = 36 cm

3rd Side = 25 cm

Semi Perimeter = \frac{Perimeter}{2}

2

Perimeter

= \frac{29+36+25}{2}

2

29+36+25

= \frac{90}{2}

2

90

= 45

Heron's Formula for finding area :

= \sqrt{s[s-a][s-b][s-c]}

s[s−a][s−b][s−c]

= \sqrt{45[45-29][45-36][45-25]}

45[45−29][45−36][45−25]

= \sqrt{45 * 16 * 9 * 20}

45∗16∗9∗20

= \sqrt{129600}

129600

= 360 cm²

∴ 360 cm² is the are of that Triangle.

aap mujhe brainlist kr dijiye pleas