find the area of triangle whose base 2a and altitude is 3a.
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Answer ⬇⬇
Base of a triangle = 2a
Altitude of a triangle=3a
Area of a triangle= 1/2×2a×3a
=1/2×6a square
=3a square.
Answer ⬇⬇
Base of a triangle = 2a
Altitude of a triangle=3a
Area of a triangle= 1/2×2a×3a
=1/2×6a square
=3a square.
Answered by
2
area of triangle=1/2×base × height
=1/2×2a×3a
=3a^2
=1/2×2a×3a
=3a^2
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