Question

find the area of triangle whose base and altitude are 3+√3 and 3-√3

Answer 1

Area of Triangle is 1/2*base *height
.˙.
=1/2*(3+√3)*(3-√3)
=1/2*3²-(√3)²
=1/2*9-3
=1/2*6
=3
Hope this helps you !!