Question

find the area of triangle whose base is 4cm and height is 3cm​

Answer 1

Step-by-step explanation:

area of triangle=B×H×1/2

=3×4=12×1/2=6cm²

Answer 2

Given

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$\rm\longrightarrow{Base\: of\: the\: triangle = 4cm}$

$\rm\longrightarrow{Height\: of\: the\: triangle = 3cm}$

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To find

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$\rm\longrightarrow{Area\: of\: the\: triangle}$

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Solution

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$\rm\longrightarrow{We\: have\: base\: and\: height\: of\: the} \\ \rm{\: \: \: \: \: \: triangle\: and\: need\: to\: find\: the\: area.}$

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$\: \: \: \: \: \: \: \: \: \:\underline{\sf{\red{Formula\: used}}}$

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$\boxed{\bf{\bigstar{Area_{(Triangle)} = \dfrac{1}{2} \times base \times height{\bigstar}}}}$

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$\: \: \: \: \: \: \: \: \: \:\underline{\sf{\red{Putting\: the\: values}}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {Area = \dfrac{1}{\cancel{2}} \times \cancel{4} \times 3}$

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$\tt:\implies\: \: \: \: \: \: \: \: {Area = 2 \times 3}$

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$\frak:\implies\: \: \: \: \: \: \: \: {\underline{\boxed{\purple{Area = 6cm^2}}}}$

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Hence,

• $\sf{Area\: of\: the\: triangle\: is\: 6cm^2.}$

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⠀⠀⠀ ⠀⠀Some Formulae

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→ Area of square = (side)²

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→ Area of rectangle = length × breadth

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→ Area of triangle = ½ × base × height

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→ Area of parallelogram = base × height

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→ Area of Circle = πr²