Question

Find the area of triangle whose base is 7cm and height is 9cm

Answer 1

Answer:31.5

Step-by-step explanation:

Area of triangle=1/2(base)(height)

therefore,

area of triangle=1/2(7 . 9)

=1/2(63)

=31.5

hope you find this helpful!

Answer 2

Given :

• Base = 7cm

• Height = 09cm

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \\ \end{gathered}\end{gathered}\end{gathered}$

To Find :

• Area of Triangle = ?

Solution :

~Formula Used

• ${\underline{\boxed{\pmb{\sf{Area = \dfrac{1}{2} \times = Base \times Height }}}}}$

Where :

• B = Base

• H = Height

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}\end{gathered}\end{gathered}$

~Calculating The Area

$\begin{gathered}\begin{gathered}\begin{gathered} {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times Base \times Height }}}} \\ \\ \\{\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times 7 \times 9 }}}} \\ \\ \\ {\dashrightarrow{\qquad{\sf{ Area = \frac{1}{2} \times 63 }}}} \\ \\ \\ {\dashrightarrow{\qquad{\sf{ Area = \cancel{\dfrac{1}{2} \times 63}}}}} \\ \\ \\ \\ {\dashrightarrow{\qquad{\sf{ Area = \red{31.5}(Approx)}}}} \\ \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\orange{\pmb{\frak{ Area = 31.5 \; {cm}^{2} }}}}}}}}\end{gathered}\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}\end{gathered}\end{gathered}</p><p>\begin{gathered}\\ \qquad{\rule{150pt}{1pt}} \end{gathered}</p><p>$

~Therefore

❛❛ Area of the given parallelogram is  31.5cm²(Approx) . ❜❜

$\begin{gathered}\begin{gathered}\begin{gathered} \\ {\underline{\rule{180pt}{9pt}}} \end{gathered} \end{gathered}\end{gathered}$