Question

find the area of triangle whose base is 8xsquare y and altitude isb3xy square​

Answer 1

Answer:

$area \: of \: triangle \: = \frac{1}{2} \times base \times height$

here it is given that

$base = 8 {x}^{2} y$

and

$height \: = 3bx {y}^{2}$

=} by substituting in formula we get,

area =

$\frac{1}{2} \: \times 8 {x}^{2} y \times 3x {y}^{2}$

=}

$12 {x}^{3} {y}^{3}$

therefore , area of triangle is 12x^3 y^3 units

Answer 2

Answer:

The area of the triangle is 12x³y³.

Step-by-step explanation:

The area of a triangle is:

$Area=\frac{1}{2}\times base\times height$

Given:

base = 8x²y

height = 3xy²

Compute the area of the triangle as follows:

$Area=\frac{1}{2}\times base\times height=\frac{1}{2}\times 8x^{2}y\times 3xy^{2}=12x^{3}y^{3}$

Thus, the area of the triangle is 12x³y³.