find the area of triangle. whose length are 78cm,50 cm, 112cm.
Answers
Answered by
1
let
a=78cm
b=50cm
c=112cm
s=(a+b+c)/2
s=(78+50+112)/2
s=240/12
s=20
area of triangle=√(s-a)(s-b)(s-c) full root
then putt the value
your answer is 30cm pl
please mark it brain list
a=78cm
b=50cm
c=112cm
s=(a+b+c)/2
s=(78+50+112)/2
s=240/12
s=20
area of triangle=√(s-a)(s-b)(s-c) full root
then putt the value
your answer is 30cm pl
please mark it brain list
Answered by
1
We can solve this by heron formula
formula=√s(s-a)(s-b)(s-c)
where s=a+b+c/2
let =78,b=50,c=112
s=120
area=√120(42)(70)(8)
=√2822400
=1680cm sq
formula=√s(s-a)(s-b)(s-c)
where s=a+b+c/2
let =78,b=50,c=112
s=120
area=√120(42)(70)(8)
=√2822400
=1680cm sq
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