Question

find the area of triangle whose length of sides are 10cm12cm and 14cm respt. use the heron's formula ​

Answer 1

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Step-by-step explanation:

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Answer 2

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To Find :

• Area of triangle whose length of sides are : 10cm , 12 cm and 14 cm

Solution :

$\large\sf{Let}\begin{cases}\sf{\bullet\:a = 10cm}\\\sf{\bullet\:b = 12cm}\\\sf{\bullet\:c = 14cm} \end{cases}$

By Heron's Formula :

$\sf \: s = \frac{a + b + c}{2}$

$\sf \: s = \frac{10 + 12 + 14}{2} \\ \\ \sf \: s= \cancel\frac{36}{2} \\ \\ \sf \: s= 18cm$

$\sf \: ar.of \triangle = \sqrt{s(s - a) (s - b)(s - c)} \\ \\ \sf \: = \sqrt{18(18 - 10)(18 - 12)(18 - 14)} \\ \\ \sf \: = \sqrt{18 \times 8 \times 6 \times 4} \\ \\ \sf \: = \sqrt{3456} \\\\\: =\underline{\boxed{58.78cm^{2}}}$

Hence

• Area of triangle is 58.78cm²

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