Question

Find the area of triangle whose perimeter 168cm and two of it sides are 50cm 60cm

Answer 1

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↪ Perimeter of the ∆ = 168 cm

↪ Two of its sides are = 50 cm and 60 cm

↪ Perimeter of ∆ = 1st side + 2nd side + 3rd side

168 = 50 + 60 + 3rd side

168 = 110 + 3rd side

168 – 110 = 3rd side

58 cm = 3rd side

According to Heron's formula ,
S = ( A + B + C ) / 2

↪ S = ( 50 + 60 + 58 ) / 2

S = 168 / 2

S = 84

↪ Area of ∆ = √S( S – A )( S – B )( S –C)

= √84( 84 – 50 )( 84 – 60 )( 84 – 58 )

= √84( 34 )( 24 )( 26 )

= √84 ( 21216 )

= √1782144

= 1334.97 cm²