Find the area of triangle whose perimeter 168cm and two of it sides are 50cm 60cm
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↪ Perimeter of the ∆ = 168 cm
↪ Two of its sides are = 50 cm and 60 cm
↪ Perimeter of ∆ = 1st side + 2nd side + 3rd side
168 = 50 + 60 + 3rd side
168 = 110 + 3rd side
168 – 110 = 3rd side
58 cm = 3rd side
According to Heron's formula ,
S = ( A + B + C ) / 2
↪ S = ( 50 + 60 + 58 ) / 2
S = 168 / 2
S = 84
↪ Area of ∆ = √S( S – A )( S – B )( S –C)
= √84( 84 – 50 )( 84 – 60 )( 84 – 58 )
= √84( 34 )( 24 )( 26 )
= √84 ( 21216 )
= √1782144
= 1334.97 cm²
↪ Perimeter of the ∆ = 168 cm
↪ Two of its sides are = 50 cm and 60 cm
↪ Perimeter of ∆ = 1st side + 2nd side + 3rd side
168 = 50 + 60 + 3rd side
168 = 110 + 3rd side
168 – 110 = 3rd side
58 cm = 3rd side
According to Heron's formula ,
S = ( A + B + C ) / 2
↪ S = ( 50 + 60 + 58 ) / 2
S = 168 / 2
S = 84
↪ Area of ∆ = √S( S – A )( S – B )( S –C)
= √84( 84 – 50 )( 84 – 60 )( 84 – 58 )
= √84( 34 )( 24 )( 26 )
= √84 ( 21216 )
= √1782144
= 1334.97 cm²
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