find the area of triangle whose perimeter is 22cm , one side is 9cm and difference of the other two sides is 3cm
Answers
Answered by
5
if sides are x,y,z then a/c to question,
x+y+z=22
x=9
y-z=3...y=3+z
Therefore, 9+3+z+z=22
2z=10
z=5
Therefore, y=8,
Now you have got all the three sides, area can be easily calculated using herons formula.
x+y+z=22
x=9
y-z=3...y=3+z
Therefore, 9+3+z+z=22
2z=10
z=5
Therefore, y=8,
Now you have got all the three sides, area can be easily calculated using herons formula.
Answered by
2
9+n+n+3= 22
so 2n+12=22
n=5
so one side is 5cm and other side is 8
so now use herons formulas.
root s(s-9)(s-5)(s-8)= ANSWER
s= semi perimeter of the triangle
so 2n+12=22
n=5
so one side is 5cm and other side is 8
so now use herons formulas.
root s(s-9)(s-5)(s-8)= ANSWER
s= semi perimeter of the triangle
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