Question

find the area of triangle whose points are (2,8) (5,-6) (-4,6)

pls send me a answer
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Answer 1

Answer:

Answer:

Plot the points in a rough diagram and take them in order.

Let the vertices be A(1,2),B(−3,4) and C(−5,−6)

Now the area of △ABC is

=

2

1

{(x

1

y

2

+x

2

y

3

+x

3

y

1

)−(x

2

y

1

+x

3

y

2

+x

1

y

3

)}

=

2

1

{(4+18−10)−(−6−20−6)}

=

2

1

(12+32)=22 sq.units.

Answer 2

45

Step-by-step explanation:

x1= 2 ; y1 = 8

x2 = 5 ; y2 =(-6)

x3 =(-4) ; y3 = 6

so by

1/2|x1(y2-y3)+ x2(y3-y1)+ x3(y1-y2)|

1/2|2*(-12)+5*(-2)+(-4)*14|

1/2|(-24)+(-10)+(-56)|

1/2*90

=45 is the answer