Question

Find the area of triangle whose side are 12,14,16 cm upto two places of decimals​

Answer 1

As the perpendicular/height is not given in the data . Therefore, we will be using HERON'S formula for calculating the Area of the Triangle. As area = 1/2 × b × h cannot be applied here.

GIVEN :- Sides if a triangle are 12cm,14cm and 16cm

TO FIND :- Area of the Triangle

ANSWER :-

Let a, b and c be sides of the Triangle.

a = 12cm

b = 14cm

c = 16cm

Now, we will calculate semi-perimeter(s)

$s = \frac{a + b + c}{2} \\ \\ \\ = \frac{12 + 14 + 16}{2} \\ \\ \\ = \frac{42}{2} \\ \\ \\ = 21cm$

HERON'S FORMULA

$area = \sqrt{s(s - a)(s - b)(s - c)}$

Here we can put values to get the answer.

$area = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ \\ = \sqrt{21(21 - 12)(21 - 14)(21 - 16)} \\ \\ \\ = \sqrt{21 \times 9 \times 7 \times 5} \\ \\ \\ = \sqrt{6615} \\ \\ = \boxed{81.33}$

Therefore, the area of the Rectangle is 81.33cmsq

Answer 2

Step-by-step explanation:

answer of the question which side is 12 14 16