Find the area of triangle whose side are 18 cm, 24 cm and 30 com.
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Answered by
0
a=18
b=24
c=30
by heron's formula,
s=(a+b+c)/2
s=36
area=√s(s-a)(s-b)(s-c)
area=7776
b=24
c=30
by heron's formula,
s=(a+b+c)/2
s=36
area=√s(s-a)(s-b)(s-c)
area=7776
Answered by
3
For this question...we have to use herons formula....
that is √s(s-a)(s-b)(s-c) s=semi perimeter = perimeter of triangle/2
so the equation will be √36(36-18)(36-24)(36-30)
after solving we get√46656 = 216cm²...
hope you got your answer......
ΔThank YouΔ
that is √s(s-a)(s-b)(s-c) s=semi perimeter = perimeter of triangle/2
so the equation will be √36(36-18)(36-24)(36-30)
after solving we get√46656 = 216cm²...
hope you got your answer......
ΔThank YouΔ
khalidkkss55:
i am confuse but thank you mam and Sir
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