find the area of triangle whose side are 26cm, 28cm, 30cm respectively.
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Answered by
43
a= 26cm
b= 28cm
c=30cm
s= a+b+c/2 =42cm
According to Heron's formula, Area of a ? is equal to root of s(s-a)(s-b)(s-c).
Therefore, area of ?= root of 42(42-26)(42-28)(42-30)
= root of 42*16*14*12
= root of 112896
= 336 cm square Answer.
b= 28cm
c=30cm
s= a+b+c/2 =42cm
According to Heron's formula, Area of a ? is equal to root of s(s-a)(s-b)(s-c).
Therefore, area of ?= root of 42(42-26)(42-28)(42-30)
= root of 42*16*14*12
= root of 112896
= 336 cm square Answer.
satindersingh2:
thanx
so much
Answered by
12
a 26
b28
c:30 a= √s(s-a)(s-b)(s-c)
s= a+b+c upon 2
a= 1upon 4 √a⁴+2(ab)²+(ac)²-b⁴+2(bc)²-c⁴
1 upon 4 √-26⁴+2.(26.28)²+2.(26.30)²-30⁴
=336cm² ans
b28
c:30 a= √s(s-a)(s-b)(s-c)
s= a+b+c upon 2
a= 1upon 4 √a⁴+2(ab)²+(ac)²-b⁴+2(bc)²-c⁴
1 upon 4 √-26⁴+2.(26.28)²+2.(26.30)²-30⁴
=336cm² ans
thanx
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