Question

Find the area of triangle whose side are 3m,4m,5m​

Answer 1

Given:-

• Side of a triangle are 3 m, 4 m and 5 m.

⠀

To find:-

• Area of the triangle.

⠀

Solution:-

Here,

• s = $\bf{\dfrac{3 + 4 + 5}{2}}$

• s = $\bf{\dfrac{12}{2}}$

• s = $\bf{6}$

⠀

★Using Heron's Formula:-

$\star{\boxed{\sf{\orange{Area = \sqrt{[s(s - a)(s - b)(s - c)]}}}}}$

⠀

$\tt\longmapsto{Area = \sqrt{[6(6 - 3)(6 - 4)(6 - 5)]}}$

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$\tt\longmapsto{Area = \sqrt{[6 \times 3 \times 2 \times 1]}}$

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$\tt\longmapsto{Area = \sqrt{36}}$

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$\tt\longmapsto{\boxed{\red{Area = 6 m^2}}}$

⠀

Hence,

• the area of triangle is 6 m².

Answer 2

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Find the area of triangle whose side are 3m,4m,5m.

$\bf  {\underline {\underline{✤ ƛƝƧƜЄƦ}}}$

➞Area of Triangle is 6m²

$\bf {\underline {\underline{✤ ƓƖƔЄƝ}}}$

• Sides of triangle 3m, 4m and 5m

$\bf {\underline {\underline{✤ ƬƠ \: \: ƇƛLƇƲLƛƬЄ}}}$

• Area of Triangle

$\bf {\underline{\underline{✤ƇƠƝƇЄƤƬ}}}$

In this question, Sides of triangle are given So, we will find area of Triangle by using Heron's Formula

$\bf {\underline {\underline{✤ ƑƠƦMƲLƛ \: \: ƬƠ \: ƁЄ \: \: ƲƧЄƊ}}}$

Heron's Formula =

$\bf\sqrt{s(s - a)(s - b)(s - c)}$

$\bf {\underline {\underline{✤ SƠԼƲƬƖƠƝ}}}$

Semi Perimeter (s) = 3+4+5/2 = 12/2 = 6m

Let a be 3m, b be 4m and c be 5m

Area of Triangle =

$\bf\sqrt{s(s - a)(s - b)(s - c)}$

$\bf \sqrt{6(6 - 3)(6 - 4)(6 - 5)}$

$\bf \sqrt{6 \times 3 \times 2 \times 1}$

$\bf \sqrt{36}$

$\bf {6m}^{2}$

Therefore, Area of triangle is 6m².

$\bf \pink{hope \: } \purple{it \: } \blue{helps \: } \red{uh..}$