Math, asked by canshika, 1 year ago

Find the area of triangle whose side are 8cm and 13cm and the perimeter is 32 cm

Answers

Answered by wwwamankumarmi
8
p of triangle=sum of three sides
32=x+13+8
32-21=x
x=11
area =1/2×11×8
area =44cm
hope it's help u
Answered by manya7112004
2
the sides be:
1'st: a
2'nd: b
3'rd: c
a+b+c= perimeter
8+13+c=32
21+c=32
c=32-21
c=11
s= perimeter/2
=32/2
=16
area=
 \sqrt{s(s - a)(s - b)(s - c)}
 \sqrt{16(16 - 8)(16 - 13)(16 - 11)}
 \sqrt{16 \times 8 \times 3 \times 11}
8 \sqrt{66}

manya7112004: Please mark me as brainliest
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