find the area of triangle whose side are in the ratio 5: 12: 13: and its perimeter is 60cm
Answers
Solution :-
Ratio of sides of a triangle = 5 : 12 : 13
Let the constant ratio be x
Sides of the triangle :
- a = 5x
- b = 12x
- c = 13x
Given perimeter = 60 cm
Semi perimeter of the triangle s = (a + b + c)/2
⇒ s = (5x + 12x + 13x)/2
⇒ s = 30x/2
⇒ s = 15x
Also, s = Perimeter/2 = 60/2 = 30 cm
⇒ s = 30
⇒ 15x = 30
⇒ x = 30/15 = 2
Sides of the triangle :
- a = 5x = 5 * 2 = 10 cm
- b = 12x = 12 * 2 = 24 cm
- c = 13x = 13 * 2 = 26 cm
Semi perimeter s = 15x = 15 * 2 = 30 cm
By using Heron's formula
Area of the triangle A = √[ s(s - a)(s - b)(s - c)
[ Where a,b,c are the sides of a triangle and s is semi perimeter ]
Substituting the value in the formula
⇒ A = √[ 30(30 - 10)(30 - 24)(30 - 26) ]
⇒ A = √[ 30(20)(6)(4) ]
⇒ A = √14400
⇒ A = 120 cm²
Hence, area of the triangle is 120 cm².
- Sides Ratio = 5 : 12 : 13 .
- Perimeter = 60cm .
- Perimeter of ∆ = sum of all 3 sides.
- Area of ∆ = √s(s-a)(s-b)(s-c) where s = semi-perimeter , a,b and c are sides of ∆ .
- Pythagoras theoram.
- Area of Right angled ∆ = 1/2 × Base × Perpendicular .
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Let sides of ∆ be = 5x , 12x and 13x Respectively .
Perimeter of ∆ = 5x + 12x + 13x = 30x .
Given,
30x = 60
→ x = 2 .
Hence, sides are ,
5×2 = 10cm, 12×2 = 24cm , 13×2 = 26cm...
Now,
semiperimeter(s) = 60/2 = 30cm.
Hence, Area of ∆ = √30(30-10)(30-24)(30-26)
→ Area of ∆ = √30*20*6*4
→ Area of ∆ = √5*6*5*4*6*4
→ Area of ∆ = 5*6*4 = 120cm² .. (Ans)
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After Finding sides of ∆ , we can see if they are pythagorean Triplets or not ,
we know that,
According to pythagoras theoram sum of square of two sides is Equal to third side ...
→ (10)² + (24)² = (26)²
→ 100 + 576 = 676
→ 676 = 676 = Proved ..
Hence, it is a Right angled ∆ , with Hypotenuse 26cm.
so,
Area of Right angled ∆ = 1/2 × 10 × 24 = 120cm² ....