find the area of triangle whose side are in the ratio 5:12:13 and is perimeter is 60 cm
Answers
Answered by
1
so make a equation that 5x+12x+13x=60cm
30x=60cm
x=2cm
side 1 = 10cm
side 2 = 24cm
side 3 = 26cm
so area of triangle is √(s(s-a)(s-b)(s-c))
s=(10+24+26)/2
s=30cm
area is √(30(30-10)(30-24)(30-26))
=√(30×20×6×4)
=√14400
=120cm²
30x=60cm
x=2cm
side 1 = 10cm
side 2 = 24cm
side 3 = 26cm
so area of triangle is √(s(s-a)(s-b)(s-c))
s=(10+24+26)/2
s=30cm
area is √(30(30-10)(30-24)(30-26))
=√(30×20×6×4)
=√14400
=120cm²
Answered by
1
Given 5x + 12x + 15x = 60
30x = 60
x = 2.
5 * 2 = 10
12 * 2 = 24
13 * 2 = 26
Area = 1/2 * b * h
= 1/2 * 10 * 24
= 120 cm.
30x = 60
x = 2.
5 * 2 = 10
12 * 2 = 24
13 * 2 = 26
Area = 1/2 * b * h
= 1/2 * 10 * 24
= 120 cm.
anu244:
then why there is 24
why not 26
because i have confusion
It is a right angled traingle
By Pythagorous theorem we know that AC^2 = AB^2 + BC^2
24^2 + 10^2 = 26^2
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