Question

find the area of triangle whose side is A= i+j+k and B=2j+3k.
also find the other side.​

Answer 1

Answer:

if i=5,j=5and k=5 then A=15cm

B=2j+ 3k=2×5+3×5=25cm

C=

AB^2=AC^2+BC^2

25^2=15^2+BC^2

BC^2=25^2-15^2

BC^2=625-225

BC^2=400

BC=root over 400

BC=20cm

Hence,the last side = 20cm

Step-by-step explanation:

so bro you understand the last side is 20 cm.