Question

find the area of triangle whose side measures 52 CM 56 cm and 60 CM respectively​

Answer 1

SOLUTION__(◕ᴗ◕✿)

Given, sides of ∆

= 52cm, 56cm and 60cm

Area∆= √s(s-a)(s-b)(s-c)

Here,

a= 52cm

b= 56cm

c= 60cm

Now,

Side= 1/2(a+b+c)

= 1/2(52+56+60)

= 1/2×168

= side= 84cm

So,

Area∆= √s(s-a)(s-b)(s-c)

= √84×(84-52)(84-56)(84-60)

= √84×32×28×24

=√2×2×3×7×2×2×2×2×2×2×7×2×2×2×3

=2^5×3×7×√2

= 672√2 cm^2 ans.

MARK BRAINLIEST✓✓