Question

find the area of triangle whose sides are 10 cm 12cm and 14 cm​

Answer 1

Answer:

58.78

Step-by-step explanation:

Use heron's formula and calculate accordingly

Semi Perimeter = (10+12+14)/2 = 36/2 = 18

Area = √((s)(s-a)(s-b)(s-c))

= √(18*8*6*4)

= √3456

= 58.78

Answer 2

Answer:

The sides of a triangle are 10 cm, 12 cm and 14 cm.

Semi Perimeter of Triangle :

$\sf \dfrac{10 + 12 + 14}{2} = \dfrac{36}{2} = 18 \: cm$

Now, By using herons formula we get,

$\sf Area = \sqrt{s(s-a) (s-b) (s-c)}$

$\sf Area = \sqrt{18(18-10) (18-12) (18-14)}$

$\sf Area = \sqrt{18 \times 8 \times 6 \times 4}$

$\sf Area = \sqrt{2 \times 3 \times 3 \times 2 \times 2 \times 2 \times 2 \times 3 \times 2 \times 2}$

$\sf Area = 24\sqrt{ 6} \: cm^{2}$