Question

find the area of triangle whose sides are 10cm, 24cmand26cm
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Answer 1

Sides of the triangle :-

• 10cm
• 24cm
• 26cm

Area of triangle :-

$\sqrt{s(s-a)(s-b)(s-c)}$

Here,

s = 10 + 24 + 26/2

= 60/2

= 30

• s = 30
• a = 10
• b = 24
• c = 26

Substituting in formula :-

→ √30(30 - 10)(30 - 24)(30 - 26)

→ √30 x 20 x 6 x 4

→ 2 x 3 x 5 x 2 x 2 x 5 x 3 x 2 x 2 x 2

→ 2 x 2 x 2 x 3 x 5

→  120

Area of triangle = 120m²

Answer 2

Answer:

: Solution :

The are of triangle whose sides are 10 cm , 24 cm ,and 26 cm .

Formula to find the area of triangle :

= √s (s - a)(s - b) (s - c).

(A ,B ,C) are sides of triangle .

= 10 + 24 + 26/2

= 60 / 2

= 30 .

= √30 ( 30 - 10 ) ( 30 - 24 ) ( 30 - 26 )

= √30 (20) (6) (4)

= √36 × 4 × 100

= 6 × 2 × 10

= 120 .

= 120