Question

find the area of triangle whose sides are 11,60 and61

Answer 1

Answer:

Step-by-step explanation:

we use the formula A= sqr of s(s-a)(s-b)(s-c)

but for that we first find s

s=a+b+c/2

  =11+60+61/2

  =132/2

  =66

now we know s so we can now find area

A=sqr of s(s-a)(s-b)(s-c)

  = sqr of 66(66-11)(66-60)(66-61)

  = sqr of 66*55*6*5

  = sqr of 108900

  =330

so, the area is 330

          thanks. liked to help you.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=330\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle =11 cm,60 cm,61 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{11+60+61}{2} \\ \\ : \implies s = \frac{132}{2} \\ \\ \green{ : \implies s =66} \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{66(66- 11)(66-60)(66- 61)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{66\times 55\times6\times 5} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{108900} \\ \\ : \implies \text{Area \: of \: triangle =}330\: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle =330\: {cm}}^{2} }$