Question

Find the area of triangle whose sides are 12 cm 6cm and 14cm

Answer 1

Step-by-step explanation:

Let a=12 b=6cm c=14 cm

semi perimeter = a+b+c/2

= 12+6+14/2

=32/2

= 16cm

By using herons formula,

$\sqrt{s}(s - a)(s - b)(s - c)$

$\sqrt{16(16 - 12)(16 - 6)(16 - 14)}$

$\sqrt{16 \times 4 \times 10 \times 2}$

$\sqrt{2 \times 8 \times 2 \times 2 \times 2 \times 5 \times 2}$

$\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 2}$

$16 \sqrt{5}$

The area of triangle is 16√5.

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