Question

Find the area of triangle whose sides are 13 cm, 14 cm and 15 cm.
​

Answer 1

Answer:

84 sq.m.

Step-by-step explanation:

Given : Sides of triangle are 13 cm,14 cm and 15 CM

To Find :find the area of the triangle

Solution:

We will use heron's formula :

$A=\sqrt{s(s-a)(s-b)(s-c)}$

Where s=$\frac{a+b+c}{2}$

a = 13

b = 14

c = 15

s=$\frac{13+14+15}{2}$

A=$\sqrt{21(21-13)(21-14)(21-15)}$

A=84A=84

Hence the area of the triangle is 84 sq.m.

Answer 2

answer:-

given sides of triangle

a=13 , b=14 , c=15

semi-perimeter= 1/2 (a +b + c) = 1/2 (13+14+15) =21

area

A =

$\sqrt{s(s - a)(s - b)(s - c)}$

A= √21 (21-13) (21-14) (21-15)

A = 84cm²

__________________________________________________________

hope this help you

please mark me as brainliest❤