Question

Find the area of triangle whose sides are 17cm ,25cm 26cm​

Answer 1

The area of the triangle is "204 $cm^{2}$".

Step-by-step explanation:

Here, a = 17 cm, b = 25 cm and c = 26 cm

∴ Semiperimetre = $\dfrac{a + b + c}{2}$

=  $\dfrac{17 + 25 + 26}{2}$ cm

=  $\dfrac{68}{2}$ cm

= 34 cm

Area of triangle(Hero's formua) = $\sqrt{s(s - a)(s - b)(s - c)}$

= $\sqrt{34(34 - 17)(34 - 25)(34 - 26)}$  $cm^{2}$

= $\sqrt{34(17)(9)(8)}$  $cm^{2}$

= 17 × 3 × 4 $cm^{2}$

= 204 $cm^{2}$

Hence, the area of the triangle is "204 $cm^{2}$".

Answer 2

The area of the triangle is "204 cm^{2}cm2 ".

Step-by-step explanation

Here, a = 17 cm, b = 25 cm and c = 26

∴ Semiperimetre = \dfrac{a + b + c}{2}2a+b+c

=  \dfrac{17 + 25 + 26}{2}217+25+26 c

=  \dfrac{68}{2}268 cm

= 34 cm

Area of triangle(Hero's formua) = \sqrt{s(s - a)(s - b)(s - c)}s(s−a)(s−b)(s−c)

= \sqrt{34(34 - 17)(34 - 25)(34 - 26)}34(34−17)(34−25)(34−26) cm^{2}cm2

= \sqrt{34(17)(9)(8)}34(17)(9)(8) cm^{2}cm2

= 17 × 3 × 4 cm^{2}cm2

= 204 cm^{2}cm2

Hence, the area of the triangle is "204 cm^{2}cm2 ".