Find the area of triangle whose sides are 20 cm, 9 cm, 10 cm
Try to solve!
Level :- HARD
Answers
Step-by-step explanation:
Given:-
A triangle whose sides are 20 cm, 9 cm, 10 cm
To find:-
Find the area of triangle whose sides are 20 cm, 9 cm, 10 cm
Solution:-
The three sides of the given triangle are :
20 cm, 9 cm, 10 cm
Sum of two sides = 9+10 = 19 < 20
Sum of two sides is less than the third side
This contradicts that
The sum of any two sides is greater than the third side
so no triangle can not be formed with this
measurements
Check:-
The three sides of the given triangle are :
20 cm, 9 cm, 10 cm
Let a = 20 cm
b= 9 cm
c= 10cm
Perimeter of a triangle = Sum of all sides units
=>P = a+b+c units
=>20+9+10 cm
=>39 cm
Perimeter of the given triangle = 39 cm
We know that
The area of a triangle whose sides are a,b, c
units is √[S(S-a)(S-b)(S-C) sq.units
where S = Perimeter/2 units
S = 39/2 cm
S= 19.5 cm
Area =√ [19.5(19.5-20)(19.5-9)(19.5-10)]
Area =√[19.5(-0.5)(10.5)(9.5)]
In this we get a negative value
square root of a negative cannot be defined
No triangle formed with this measurements
Used formula:-
The sum of any two sides is greater than the third side this is called inequality of a triangle