Find the area of triangle whose sides are . 25 cm, 26 cm, 17 cm
Answers
Answered by
2
Answer:
The area of the triangle is "204 cm^{2}cm
2
".
Step-by-step explanation:
Here, a = 17 cm, b = 25 cm and c = 26 cm
∴ Semiperimetre = \dfrac{a + b + c}{2}
2
a+b+c
= \dfrac{17 + 25 + 26}{2}
2
17+25+26
cm
= \dfrac{68}{2}
2
68
cm
= 34 cm
Area of triangle(Hero's formua) = \sqrt{s(s - a)(s - b)(s - c)}
s(s−a)(s−b)(s−c)
= \sqrt{34(34 - 17)(34 - 25)(34 - 26)}
34(34−17)(34−25)(34−26)
cm^{2}cm
2
= \sqrt{34(17)(9)(8)}
34(17)(9)(8)
cm^{2}cm
2
= 17 × 3 × 4 cm^{2}cm
2
= 204 cm^{2}cm
2
Hence, the area of the triangle is "204 cm^{2}cm
2
".
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Answer:
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