Question

Find the area of triangle whose sides are 27cm, 36cm and 45cm. Also find the altitude?​

Answer 1

Answer:

Step-by-step explanation:

Let-

1. a = 27cm
2. b = 36 cm
3. c = 45 cm

•°• Semi-perimeter (s) = Perimeter ÷ 2

= (27 + 36 + 45) ÷ 2

= 108 ÷ 2

= 54 cm

We know that, area of a ∆

$= \sqrt{s \times (s - a)(s - b )(s - c)}$

$= \sqrt{54(54 - 27)(54 - 36)(54 - 45)}$

$= \sqrt{54 \times 27 \times 18 \times 9}$

$= \sqrt{1458 \times 162}$

$= 236196$

•°• Hence, the area of the given triangle is 2,36,196 cm^2.

Adiós! Hope this helps you!