Find the area of triangle whose sides are 42 cm 34cm and 20cm
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Answered by
3
a = 42
b = 34
c = 20
s = ( 42 + 34 +20) /2 = 96 /2 = 48
(s - a) = ( 48 - 42) = 6
(s - b) = (48 - 34) = 14
(s - c) = ( 48 - 20) = 28
Now,
Area = sqrt [ s ( s-a) (s-b) (s-c)]
= sqrt ( 48 × 6 × 14 × 28)
= sqrt ( 8 × 6 × 6 × 7 × 2 × 2 × 2 × 7)
= sqrt ( 6 × 6 × 7 × 7 × 16 × 2 × 2)
= 6 × 7 × 4 × 2
= 7 × 48
= 336 cm^2
b = 34
c = 20
s = ( 42 + 34 +20) /2 = 96 /2 = 48
(s - a) = ( 48 - 42) = 6
(s - b) = (48 - 34) = 14
(s - c) = ( 48 - 20) = 28
Now,
Area = sqrt [ s ( s-a) (s-b) (s-c)]
= sqrt ( 48 × 6 × 14 × 28)
= sqrt ( 8 × 6 × 6 × 7 × 2 × 2 × 2 × 7)
= sqrt ( 6 × 6 × 7 × 7 × 16 × 2 × 2)
= 6 × 7 × 4 × 2
= 7 × 48
= 336 cm^2
Answered by
0
a = 42 cm , b = 34 cm and c = 20 cm.
semi perimeter = 1/2 × a+b+c = 48 cm.
area of triangle = √s(s-a)(s-b)(s-c) = √48×6×14×28 = 336 cm².
semi perimeter = 1/2 × a+b+c = 48 cm.
area of triangle = √s(s-a)(s-b)(s-c) = √48×6×14×28 = 336 cm².
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