Question

find the area of triangle whose sides are 5 and 6 cm and base is 4 cm​

Answer 1

Answer:

the answer is 15/4(7)^-2 cm^2

Answer 2

Answer:

$\frac{15}{4} {7cm}^{2}$

Step-by-step explanation:

Given :

$a \: = \: 5 \: cm$

$b \: = 6 \: cm \:$

$c \: = \: 4 \: cm$

$s= \frac{a + b + c}{2} = \frac{5 + 6 + 4}{2} = \frac{15}{2}$

$∴ area \: of \: the \: triangle \: = \\ \\ \sqrt{s} (s - a)(s - b)(s - c) \\ \sqrt{ \frac{15}{2} } \times \frac{15}{2} - 4 \: ( \frac{15}{2} - 5) \: ( \frac{15}{2} - 6) \\ = \sqrt{ \frac{15}{2} } \times \frac{7}{2} \times \frac{5}{2} \times \frac{3}{2} = \frac{15}{4} \sqrt{7cm {}^{2} }$

HOPE THIS HELPS YOU!!!! IF YOU LIKE THIS ANSWER PLS MARK ME AS THE BRAINLIEST !!! AND DO FOLLOW ME!!!