find the area of triangle whose sides are 5cm, 12cm and 13cm also find the altitude corresponding to the longest side
Answers
Answer:
Given, sides of triangle 5 cm, 12 cm, 13 cm.
Now semi perimeter, s= =
2
sum of the sides of triangle
=
2
5+12+13
=15 cm
Using heron's formula, Area of triangle=
s(s−a)(s−b)(s−c)
=
15(15−5)(15−12)(15−13)
=
15×10×3×2
=30cm
2
Using altitude, area of triangle =
2
1
× base × altitude =30cm
2
=
2
1
×13× altitude =30
= altitude =
13
30×2
=4.61 cm
So, altitude corresponding to largest side is 4.61 cm.
A
Step-by-step explanation:
Now semi perimeter, s=
semi perimeter, s= 2
semi perimeter, s= 2sum of the sides of triangle
=
= 2
= 25+12+13
= 25+12+13
= 25+12+13 =15 cm
= 25+12+13 =15 cmUsing heron's formula, Area of triangle=
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c)
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c)
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c)
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) =
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13)
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13)
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13)
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) =
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2 Using altitude, area of triangle =
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2 Using altitude, area of triangle = 2
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2 Using altitude, area of triangle = 21
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2 Using altitude, area of triangle = 21
= 25+12+13 =15 cmUsing heron's formula, Area of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2 Using altitude, area of triangle = 21 × base × altitude =30cm 2
=
= 2
= 21
= 21
= 21 ×13× altitude =30
= 21 ×13× altitude =30= altitude =
= 21 ×13× altitude =30= altitude = 13
= 21 ×13× altitude =30= altitude = 1330×2
= 21 ×13× altitude =30= altitude = 1330×2
= 21 ×13× altitude =30= altitude = 1330×2 =4.61 cm
= 21 ×13× altitude =30= altitude = 1330×2 =4.61 cmSo, altitude corresponding to largest side is 4.61 cm.