Question

find the area of triangle whose sides are 5cm,8cm,13cm.
a)2√130cm²
b)0cm²
c)2√65cm²
d)4√165cm²​

Answer 1

a)2√130cm²

Step-by-step explanation:

Semi perimeter of triangle = a + b + c / 2

• here a, b and c are the given sides of triangle.

a = 5 cm

b = 8 cm

c = 13 cm

semi perimeter ( S ) = 5 + 8 + 13 / 2

= 26 / 2

= 13

Area of triangle =

$\sqrt{s (s - a)(s - b)(s - c)}$

$\sqrt{13(13 - 5)(13 - 8)(13 - 13}$

$\sqrt{13(8 \times 5)}$

$\sqrt{13 \times 40}$

$\sqrt{520}$

$= \: 2 \sqrt{130} cm {}^{2}$

$\sf\red{hope\:it\:helps\:you}$