Question

find the area of triangle whose sides are 80 cm, 48cm, 64 cm . Also find the altitude corresponding to the length 64 cm

Answer 1

Let a=80 , b=48, c=64
semi-perimeter=a+b+c/2

80+48+64/2

192/2 = 96

Using Heron's Formula
=√s(s-a)(s-b)(s-c)
=√96(96-80)(96-48)(96-64)
=√96(16)(48)(32)
=√(4*4*2*3)(4*4)(4*4*3)(4*4*2)
=√4*4*4*4*4*4*4*4*3*3*2*2
=4*4*4*4*3*2
=1536 sq. unit

Answer 2

Answer:

1536 sq.unit

Step-by-step explanation:

Let a=80 , b=48, c=64

semi-perimeter=a+b+c/2

80+48+64/2

192/2 = 96

Using Heron's Formula

=√s(s-a)(s-b)(s-c)

=√96(96-80)(96-48)(96-64)

=√96(16)(48)(32)

=√(4*4*2*3)(4*4)(4*4*3)(4*4*2)

=√4*4*4*4*4*4*4*4*3*3*2*2

=4*4*4*4*3*2

=1536 sq. unit