Question

Find the area of triangle whose sides are 9 cm, 12 cm and 15 cm.​

Answer 1

$s = \frac{9 + 12 + 15}{2} \\ \\ s = \frac{36}{2} \\ \\ s = 18 \\ \\ area = \sqrt{18(18 - 9)(18 - 12)(18 - 15)} \\ \\ area = \sqrt{18 \times 9 \times 6 \times 3 } \\ \\ area = 18 \times 3 \\ \\ area = 54 {cm}^{2}$

Answer 2

Answer:

$54cm^{2}$

Step-by-step explanation:

$\frac{9+12+15}{2} \\A=\sqrt{18(18-9)(18-12)(18-15)} \\A=\sqrt{18*9*6*3}\\A=18*3\\A=54cm^{2}$

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