find the area of triangle whose sides are along the lines x=3 , y=0 & 4x+5y=20
Answers
Answered by
178
Given that,
X = 3
Y = 0
&
4X + 5Y = 20
First put X = 3 in the equation we will get
4 × 3 + 5Y = 20
Y = 8/5
Now, put Y = 0 in the equation we will get
4X + 5 × 0 = 20
X = 5
Area of the triangle wll be = 1/2 × 5 × 8/5
= 4 unit²
X = 3
Y = 0
&
4X + 5Y = 20
First put X = 3 in the equation we will get
4 × 3 + 5Y = 20
Y = 8/5
Now, put Y = 0 in the equation we will get
4X + 5 × 0 = 20
X = 5
Area of the triangle wll be = 1/2 × 5 × 8/5
= 4 unit²
Answered by
17
Answer: 4 unit square
Step-by-step explanation:
X = 3
Y = 0
4X + 5Y = 20
First put X = 3 in the equation we will get
4 × 3 + 5Y = 20
Y = 8/5
Now, put Y = 0 in the equation we will get
4X + 5 × 0 = 20
X = 5
Area of the triangle wll be = 1/2 × 5 × 8/5
= 4 unit²
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