find the area of triangle whose sides are in ratio 4:5:6 and perimeter is 300 ..pls ans it fast
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ɢɪᴠᴇɴ
- Perimeter of triangle = 300
- Sides = 4x, 5x and 6x
ᴛᴏ ғɪɴᴅ
- Area of triangle.
ʟᴇᴛ, ᴛʜᴇ ʀᴀᴛɪᴏs ʙᴇ ᴛʜᴇ ᴍᴜʟᴛɪᴘʟᴇ ᴏғ x.
sᴏ, ᴅɪᴍᴇɴsɪᴏɴs ᴡɪʟʟ ʙᴇ
- 4x , 5x and 6 x
FORMULA
1.
2.
NOW
ᴅɪᴍᴇɴsɪᴏɴs
- 4x = 4×20 =80 __(a)
- 5x = 5×20 =100 __(b)
- 6x = 6×20 = 120 __(c)
ɴᴏᴡ
ʙʏ ᴜsɪɴɢ ʜᴇʀᴏɴ's ғᴏʀᴍᴜʟᴀ
ᴛʜᴇʀᴇғᴏʀᴇ
AREA = 3968.6
HOPE THIS ANSWER WILL HELP YOU!!
Answered by
10
Given :
- Sides are in ratio 4:5:6
- Perimeter is 300
To find :
- Area of triangIe
SoLution :
As sides are in ratio of 4:5:6 .
Let the sides be 4x, 5x, 6x units.
Now we know that :
⇒ Perimeter of Δ = Sum of 3 sides of Δ
ATQ,
⇒ 4x + 5x + 6x = 300
⇒ 15x = 300
⇒ x = 300/15
⇒ x = 20 units.
Now finding sides of Δ :
- 4x = 4 × 20 = 80 units.
- 5x = 5 × 20 = 100 units.
- 6x = 6 × 20 = 120 units.
Now using Heron's formuLa :
⇒ Area of Δ = √[s(s - a)(s - b)(s - c)]
Where, s = semi perimeter
⇒ s = 300/2
⇒ s = 150 units.
Substituting :
⇒ Area of Δ = √[150(150 - 80)(150 - 100)(150 - 120)]
⇒ Area of Δ = √[150 × 70 × 50 × 30]
⇒ Area of Δ = √15750000
⇒ Area of Δ = 3968.63 unit²
∴ Area of Δ = 3968.63 unit²
Anonymous:
Nice :)
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