find the area of triangle whose sides are measures 24cm, 34cm and 20cm. also find the height corresponding to the longest side.
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Answered by
0
Answer:
area of a triangle=1/2 base x height
let the base of the triangle be 24cm and the height be 20 cm,
then,
=12x20
=240sq.cm
Answered by
1
Step-by-step explanation:
a=24
b=34
c=20
semi perimeter=(24+34+20)/2
=78/2
=39
a=√s(s-a)(s-b)(s-c)
√39(39-24)(39-34)(39-20)
=√39*15*5*19
=√55575
=235.74
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