Question

Find the area of triangle whose sides are of
measurment 5cm , 12cm and 13cm
​

Answer 1

Answer:

your answer is above

please mark me as brainliest

Answer 2

Answer:

Step-by-step explanation:

Sides of Triangular field are 5cm ,12cm,13cm.Perimeter of Triangular field = S + S + S= 5cm + 12cm + 13cm= 30cm

$Area \: of \: Triangular \: Field \\ A=\sqrt{s(s﹣a)(s﹣b)(s﹣c)}$

$s= \frac{a + b + c}{2} \\ = \frac{30cm}{2} \\ = 15cm$

$Solving \: for \: A \\ \ \ = \sqrt{ s (s﹣a)(s﹣b)(s﹣c)} \\ = \sqrt{15(15 - 12)(15 - 13)(15 - 5)} \\ = \sqrt{15(3)(2)(10)} \\ = \sqrt{15 \times 15 \times 2 \times 2} \\ = 15 \times 2 \\ {30cm}^{2}$