Question

find the area of triangle whose sides is 7cm,6cm,and 9cm.​

Answer 1

Answer:

height = ?

Step-by-step explanation:

actually to find area of triangle height is needed

area of triangle= 1/2 × height× base

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=20.97\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle =7 cm,6 cm,9 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{7+6+9}{2} \\ \\ : \implies s = \frac{22}{2} \\ \\ \green{ : \implies s =11 } \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{11(11- 7)(11-6)(11- 9)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{11\times 4\times5\times 2} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{440} \\ \\ : \implies \text{Area \: of \: triangle =}20.97\: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle =20.97\: {cm}}^{2} }$