find the area of triangle whose sife are 91 98 105 m in length find the height responding to the longest side using herons formula
Answers
Answered by
3
91+98+105/2 = 294/2=147
√(147*(147-91)*(147-98)*(147-105))
√(147*56*49*42)
√(3*7*7*2*2*2*7*7*7*2*3*7)
3*7*2*7*2*7
21*14*14
4116 m^2
the area if e triangle is 4116 m2
the height of the triangle is equal to
area multiplied by 2 the whole divided by the base
(4116*2)/105=78.4m
therefore the area of the triangle is 4116 m2 and the height of the triangle is 78.4m
√(147*(147-91)*(147-98)*(147-105))
√(147*56*49*42)
√(3*7*7*2*2*2*7*7*7*2*3*7)
3*7*2*7*2*7
21*14*14
4116 m^2
the area if e triangle is 4116 m2
the height of the triangle is equal to
area multiplied by 2 the whole divided by the base
(4116*2)/105=78.4m
therefore the area of the triangle is 4116 m2 and the height of the triangle is 78.4m
Similar questions