Question

Find the area of triangle whose three sides are 10m and 12m and 4m.

Answer 1

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$\rightarrow\underline\textsf{Here}$

a = 10

b = 12

c = 4

$\bigstar\sf\underline{By \:using \:heronz \:formula }$

$\rightarrow\sf{S = \dfrac{a + b + c}{2} }$

$\rightarrow\sf{S =\dfrac{10 + 12 + 4}{2} }$

$\rightarrow\sf{S = \dfrac{26}{2} }$

$\rightarrow\textsf{S = 13}$

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$\sf\bigstar{Area\: of \:triangle = \sqrt{s(s - a)(s - b)(s - c)} }$

$\rightarrow\sqrt{13(13 - 10)(13 - 12)(13 - 4)}$

$\rightarrow\sqrt{13 \times 3 \times 1 \times 9}$

$\rightarrow\textsf3\sqrt{13 \times 3 }$

$\rightarrow\textsf3\sqrt{39}$

$\rightarrow\textsf3 \times 6.244$

$\sf\rightarrow{18.732{m}^{2}}$

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