find the area of triangle whose two sides are 8cm and 11cm and it's semi perimeter is 16cm
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area of triangle =√s(s-a)(s-b)(s-c)
in given triangle
a=8
b=11
c=?
s=16
perimeter=16×2
=32=8+11+c
32=19+c
c=32-19
c=13
area=√16(16-8)(16-11)(16-13)
√16(8)(5)(3)
4×4×2×2×2×5×3
4×2√2×5×3
8√30cm^2
in given triangle
a=8
b=11
c=?
s=16
perimeter=16×2
=32=8+11+c
32=19+c
c=32-19
c=13
area=√16(16-8)(16-11)(16-13)
√16(8)(5)(3)
4×4×2×2×2×5×3
4×2√2×5×3
8√30cm^2
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3
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