Question

Find the area of triangle whose vertex are1
- 1 - 4 ,6. - 3 and minus 5

Answer 1

SOLUTION :-

Let the vertices of the triangle be,

• A ( 1, -1 )

• B ( -4 , 6 )

• C ( -3 , -5 )

$\boxed{\bf Area \ of \ triangle = \dfrac{1}{2} \times [ \ x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2) \ ] }$

Here,

$\bullet\sf \ x_1=1 \ , \ y_1= -1 \\\\\bullet \ x_2=-4 \ , \ y_2= 6 \\\\\bullet \ x_3= -3 \ , \ y_3= -5$

$\longrightarrow\sf \ \dfrac{1}{2} \times [ \ 1(6-(-5))+-4(-5-(-1))+-3\times (-1-6) \ ] \\\\\longrightarrow\sf \dfrac{1}{2} \times [ \ 1(6+5)+-4(-5+1)+-3(-1-6) \ ] \\\\\longrightarrow \dfrac{1}{2} \times [ \ (1\times 11)+(-4\times -4)+(-3\times -7) \ ] \\\\\longrightarrow \dfrac{1}{2} \times [ \ 11+16+21 \ ] \\\\\longrightarrow \dfrac{1}{2} \times 48\\\\\longrightarrow \bf 24$

Area of the triangle = 24 units

Answer 2

Answer:

Answer is in attachment.

IT'S 100000% CORRECT