find the area of triangle whose verticals are :(I) (2,3),(-1,0),(2,-4)
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Answer:
the area of triangle =21/2 SQ.UNITS
Step-by-step explanation:
A(2,3) B(-1,0) C(2,-4)
X1=2 X2=-1 X3=2
Y1=3 Y2=0 Y3= -4
1/2 {x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}
1/2 {2(0-(-4)) + (-1) (-4-3) + 2(3-0)}
1/2 {8-(-7)+6}
1/2 {8+7+6}
1/2 * 21
21/2
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