Question

Find the area of triangle whose vertices (0,0) (1,2) (4,3) ?​

Answer 1

Answer:

Let A(0,0)=(x1,y1), B(1,2)=(x2,y2) and C(4,3)=(x3,y3)

ar(ABC)=1÷2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}

ar(ABC)=1÷2{0(2-3)+1(3-0)+4(0-2)}

ar(ABC)=1÷2{0(-1)+1(3)+4(-2)}

ar(ABC)=1÷2(0+3-8)

ar(ABC)=1÷2(-5)

ar(ABC)=-2.5 sq. units

Step-by-step explanation:

Answer 2

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