Question

find the area of triangle whose vertices are (0,0) (4,0) (0,5).​

Answer 1

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Given Points are (0,0),(6,0),(4,3)

comparing with (x

1

,y

1

),(x

2

,y

2

),(x

3

,y

3

)

∴ Area of triangle =

2

1

∣x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)∣

=

2

1

∣0(0−3)+6(3−0)+4(0−0)∣

=

2

1

∣0+18+0∣=9