Question

Find the area of triangle whose vertices are (0,0) (a,0)(0,b)

Answer 1

Answer:

Area of triangle=1/2{x1(y2- y3)+x2(y3-y1)+x3(y1-y2)}hence, 1/2{0(2-0)+0( 0-0)+2(0-2)} =1/2{0+0-2} =-2/2=-1.

Answer 2

Answer:

Answer

Step-by-step explanation:

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