Find the area of triangle whose vertices are (0,2) (3,0) (3,2)
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Answer:ar. of triangle = 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
1/2[0(0-2)+3(2-2)+3(2-0)]
=1/2[0+0+6]
=1/2(6)
=3.
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