Question

Find the area of triangle whose vertices are (1,-1), (-4,6) and (-3,-5).
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Answer 1

Draw graphs of 3x=4y+32 and 3x+4y=16. find the coordinates of the vertices of the triangle formed by lines with y+2=0. find the perimeter of the triangle

Find the area of triangle whose vertices are (1,-1), (-4,6) and (-3,-5).

Answer 2

Area of triangle = 1/2 × [1(6 + 5) – 4(–5 + 1) – 3(–1 – 6)]

= 1/2 × [11 + 16 + 21]

= 48/2

= 24 sq. units.